: Ok, apparently, there's no mass figure for even the regular Halcyon-class
: cruiser, so I'll stick with your 1.1*10^9 kg total mass figure. Now, I'll
: do calculus to consider the diminishment of gravitational acceleration
: during the climb.

: CAUTION: MATHS AHEADS

: Defined integral from (0+Reach's radius) to (200*10^3 + Reach's radius) of
: [m*(G*M/r^2)*dr], where m is the ship's mass (1.1*10^9), M is Reach's mass
: [9.15*10^24 (figured out by its 1.08G and it's diameter*)] and G is the
: universal gravity constant (6.674*10^-11), all in SI units, of course.

: That figures about 8.6*10^16 Joules, a whole order of magnitude above your
: figure, which is odd. It should've been slightly less. Maybe the more
: accurate gravitational acceleration makes up for it.

: *Solve [10.8584=(6.674*10^-11 * M)/(7.5*7.5*10^12)] for M, if anyone's
: interested.

I guess one of the unknowns is still the Autumn's mass. Wonder if it can be estimated from some canonical sources.

And which Autumn? The Halo 1 and Halo Reach versions aren't even the same length, width and height.