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Re: It's hard to believe such a clammily… of a pos

In Response To: Re: It's hard to believe such a clammily… of a pos (Cody Miller)

: Okay this is easy.

: (P.E)= m*g*h

: 1085264000kg for the fuel plus 8128371kg for the ship's weight means you have

: to lift 1093392371kg.

: Let's say 200km to be off the planet.

: PE= 1093392371kg*200000m*9.8m/s^2

: So it would take 2143049047160000.2 jules of energy TWO QUADRILLION JULES.

: That's 20 hiroshimas.

*joules (sorry, can't help myself)

Ok, apparently, there's no mass figure for even the regular Halcyon-class cruiser, so I'll stick with your 1.1*10^9 kg total mass figure. Now, I'll do calculus to consider the diminishment of gravitational acceleration during the climb.

CAUTION: MATHS AHEADS

Defined integral from (0+Reach's radius) to (200*10^3 + Reach's radius) of [m*(G*M/r^2)*dr], where m is the ship's mass (1.1*10^9), M is Reach's mass [9.15*10^24 (figured out by its 1.08G and it's diameter*)] and G is the universal gravity constant (6.674*10^-11), all in SI units, of course.

That figures about 8.6*10^16 Joules, a whole order of magnitude above your figure, which is odd. It should've been slightly less. Maybe the more accurate gravitational acceleration makes up for it.

*Solve [10.8584=(6.674*10^-11 * M)/(7.5*7.5*10^12)] for M, if anyone's interested.